| [ QuizWit ] in KIDS 글 쓴 이(By): iLUSiON (화려한집념) 날 짜 (Date): 2003년 3월 27일 목요일 오전 09시 09분 54초 제 목(Title): Re: random walk 2. someone explain what the second guy is doing. i think P(0,y,t) = p P(0,y-1,t-1) + (1-p) P(0,y+1,t-1). with the innitial condition P(0,0,0)=1 and boundary condition P(0,y,0) = 0 for all y other than 0. now please someone solve it for me. ^^ hehe.... \sum_t P(0,y,t) = p \sum_t P(0,y-1,t-1) + (1-p) \sum_t P(0,y+1,t-1) P(0,y) = p P(0,y-1) + (1-p) P(0,y+1). oh coool.... oh i got it. now what? hehe... ok... solve it guys will ya. ^^ iLUSiON whitepolarcow@hotmail.com |