| [ CnUnix ] in KIDS 글 쓴 이(By): pkyoung () 날 짜 (Date): 2002년 3월 27일 수요일 오후 03시 09분 30초 제 목(Title): Re: [Q] pow 함수의 사용법 (i=0,pow=0.000000 x=1 arms=40000000)(i=0,pow=0.000000 x=3 arms=40000000)(i=0,pow=0.000000 x=7 arms=40000000)(i=0,pow=0.000000 x=7 arms=40000000)(i=0,pow=0.000000 x=7 arms=40000000)(i=0,pow=0.000000 x=7 arms=40000000)(i=0,pow=0.000000 x=47 arms=40000000)(i=0,pow=0.000000 x=47 arms=40000000) (i=2,pow=0.000000 x=0 arms=40000000)(i=2,pow=0.000000 x=0 arms=40000000)(i=2,pow=0.000000 x=0 arms=40000000)(i=2,pow=0.000000 x=0 arms=40000000)(i=2,pow=0.000000 x=0 arms=40000000)(i=2,pow=0.000000 x=20 arms=40000000)(i=2,pow=0.000000 x=60 arms=40000000)(i=2,pow=0.000000 x=60 arms=40000000) (i=4,pow=0.000000 x=1 arms=40000000)(i=4,pow=0.000000 x=1 arms=40000000)(i=4,pow=0.000000 x=5 arms=40000000)(i=4,pow=0.000000 x=5 arms=40000000)(i=4,pow=0.000000 x=15 arms=40000000)(i=4,pow=0.000000 x=35 arms=40000000)(i=4,pow=0.000000 x=75 arms=40000000)(i=4,pow=0.000000 x=75 arms=40000000) (i=6,pow=0.000000 x=0 arms=40000000)(i=6,pow=0.000000 x=0 arms=40000000)(i=6,pow=0.000000 x=0 arms=40000000)(i=6,pow=0.000000 x=0 arms=40000000)(i=6,pow=0.000000 x=0 arms=40000000)(i=6,pow=0.000000 x=0 arms=40000000)(i=6,pow=0.000000 x=0 arms=40000000)(i=6,pow=0.000000 x=0 arms=40000000) (i=8,pow=0.000000 x=29 arms=40000000)(i=8,pow=0.000000 x=29 arms=40000000)(i=8,pow=0.000000 x=29 arms=40000000)(i=8,pow=0.000000 x=29 arms=40000000)(i=8,pow=0.000000 x=39 arms=40000000)(i=8,pow=0.000000 x=59 arms=40000000)(i=8,pow=0.000000 x=ffffff99 arms=40000000)(i=8,pow=0.000000 x=ffffff99 arms=40000000) (i=10,pow=0.000000 x=2 arms=40000000)(i=10,pow=0.000000 x=2 arms=40000000)(i=10,pow=0.000000 x=2 arms=40000000)(i=10,pow=0.000000 x=2 arms=40000000)(i=10,pow=0.000000 x=12 arms=40000000)(i=10,pow=0.000000 x=32 arms=40000000)(i=10,pow=0.000000 x=32 arms=40000000)(i=10,pow=0.000000 x=32 arms=40000000) (i=12,pow=0.000000 x=ffffff89 arms=40000000)(i=12,pow=0.000000 x=ffffff89 arms=40000000)(i=12,pow=0.000000 x=ffffff89 arms=40000000)(i=12,pow=0.000000 x=ffffff91 arms=40000000)(i=12,pow=0.000000 x=ffffff91 arms=40000000)(i=12,pow=0.000000 x=ffffff91 arms=40000000)(i=12,pow=0.000000 x=ffffff91 arms=40000000)(i=12,pow=0.000000 x=11 arms=40000000) (i=14,pow=nan x=2 arms=40000000)(i=14,pow=0.000000 x=2 arms=40000000)(i=14,pow=0.000000 x=2 arms=40000000)(i=14,pow=0.000000 x=2 arms=40000000)(i=14,pow=nan x=12 arms=40000000)(i=14,pow=nan x=32 arms=40000000)(i=14,pow=0.000000 x=32 arms=40000000)(i=14,pow=0.000000 x=32 arms=40000000) 일단 올리신 프로그램은 제 시스템에서는 잘(?) 돌아가네요.. (x를 두번 정의한거 char로 고치고, byte를 char로 바꾸고요.) 에러없이.. rh7.2, gcc2.96입니다.. 근데 prinf( "%f\n",(char)((double)4.) )); 이라는 코드는 값이 얼마가 나와야 잘돌아가는걸까요? |